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STUDENT SECTION
Ready to talk about the "true odds" bets?
Oh don't be such a wuss. The true odds bets are fun to learn. They are based on the combinations of a pair of dice such as the amount of "ways" we can roll a number verses a 7. Example: There are five ways to roll the 6. There are six ways to roll the 7. Therefore the odds of winning when the point is 6 on the pass line are 6 to 5 (6:5)- The wager we bet behind the pass line is called an odds bet. In this example each $5 would win $6 and the original pass line wins even money. TELL ME MORE, NEXT QUESTION PLEASE
The "true odds" wagers are based on the combinations of a pair of dice such as the amount of "ways" we can roll a number verses a 7. Example: There are five ways to roll the 6. There are six ways to roll the 7. Therefore the odds of winning when the point is 6 on the pass line are 6 to 5 (6:5) The wager we bet behind the pass line is called an odds bet. In this example each $5 would win $6 and the original pass line wins even money.
TRUE! The "true odds" wagers are indeed based on the combinations of a pair of dice such as the amount of "ways" we can roll a number verses a 7. Example: There are five ways to roll the 6. There are six ways to roll the 7. Therefore the odds of winning when the point is 6 on the pass line are 6 to 5 (6:5) The wager we bet behind the pass line is called an odds bet. In this example each $5 would win $6 and the original pass line wins even money.
There are six ways to roll a 7 There are five ways to roll 6 or 8 There are four ways to roll 5 or 9 There are three ways to roll 4 or 10
TRUE! You better memorize this There are six ways to roll a 7 There are five ways to roll 6 or 8 There are four ways to roll 5 or 9 There are three ways to roll 4 or 10
So if there are three ways to roll a 4 or 10 then the odds must be 6 to 3 (6:3) against a 7 and the same theory holds true for the 5 & 9 being that each one can be made four different ways thus the odds against a 7 are 6:4 ....In a nutshell.... 4/10....6:3 odds 5/9......6:4 odds 6/8......6:5 odds
Yes it is true. The odds are indeed based against the 7 of which there are six ways to roll. 4/10....6:3 odds......this is reduced down to 2:1 (6:3 & 2:1 are the same) 5/9......6:4 odds......same thing here, 6:4 reduced down to 3:2 6/8......6:5 odds......Can't reduce these numbers. Must remain the same
Whatever, next question please
When we talk about odds try to remember that the first number is what you win and the second number is what you wager. Example, 6:5 odds - You will win $6 for each $5 wagered. Now lets check out a horse race shall we? Of the odds offered below, which is favored to win? 3:2 2:1 9:5 7:5 6:5
3:2 2:1 9:5 7:5 6:5 Sure hope you picked 6:5 for that would be the favorite and the 2:1 would be the underdog. Now, assume we wagered $10 on each. A $10 wager @ 3:2 = $15 A $10 wager @ 2:1 = $20 A $10 wager @ 9:5 = $18 A $10 wager @ 7:5 = $14 A $10 wager @ 6:5 = $12 As you can see, the 6:5 horse or whatever pays the least thus makes it the favorite to win over the others and the 2:1 wins the most thus should be considered the 'long shot'.
Here is another horse race. What horse is favored to win? 3:2 2:1 9:5 7:5 2:3 6:5
3:2 2:1 9:5 7:5 2:3 6:5
Remember, when studying odds, the first number is what you win and the second number is what you bet. Did you pick 2:3 as the favored horse in our hypothetical example? Should have because whenever you wager more to win less you are betting on the 'heavy' favorite. It's no guarantee you'll win, you are simply predicted to win.
Now let us apply that same concept to the "true odds" offered on a craps game. Which is the 'favorite to win'
6:5 3:2 2:1 5:6 2:3 1:2
Study the odds then click here
6:5 (Bet 5 win 6) 3:2 (Bet 2 win 3) 2:1 (Bet 1 win 2) 5:6 (Bet 6 win 5) 2:3 (Bet 3 win 2) 1:2 (Bet 2 win 1)
Betting 2 and only winning 1 would be considered the favorite
Betting less to win more is considered TAKING ODDS
Betting more to win less is considered LAYING ODDS
Statement is true
Betting less to win more is considered TAKING ODDS
Betting more to win less is considered LAYING ODDS
6:5 odds on point 6 or 8
$30 = $35
Nope, if I wager $25 at 6:5 odds (point 6 or 8) Each 5 wins 6, therefore 30=36 There are six 5's in 30, 6x6 would be the answer. 36
At 6:5 odds (point 6 or 8) would you consider the following payoffs to be correct?
10=12, 25=30, 15=18, 40=48, 50=60, 20=24, 35=42
6:5 odds (point 6 or 8)
10=12, 25=30, 15=18, 40=48, 50=60, 20=24, 35=42
Each 5 wins 6, therefore all the above figures are correct
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